CoE questions

PFY p.121

 19 a) 50 x 10= 500N

  b) gpe = mgh = 10 x 50 x 4 = 2000J

Collins, p.91

3 a) gpe = mgh = 35 x 10 x 10,500J

   b) gpe at top = KE at bottom

       KE = .5m v2 = 10,500 = .5 x 35 x v2

       v2 = 600

       v = 24.5m/s

   c) not all of the gpe is transferred to KE, some energy is wasted due to friction